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设a1a2a3b1b2b3c1c2c3等于1,那么
设a1a2a3b1b2b3c1c2c3=2
设a1=2b1+3b2-b3
设a=a11a12a13a21a22a23a31a32a33
设a1b1+a2b2+a3b3=a,求(ba)n
设a1=(a,3,2),a2=(2,-1,3)
设a=a1b1 a1b2
设a11a12a13a21a22a23a31a32a33=m≠0
设a1=1,a2=2,3an+2
设a1ia23a35a44a5j
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