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a11a12a13a21a22a23a31a32a33=1/2
a11a21+a12a22+a13a23
a11a23-a21a13
a11a22a33a44
a11+a22+a33=λ2λ3
a11a21+a12a22+a13a23=0
a11a12a13a21a22a23a31a32a33等于2
a11a12a21a22
a11a12a13a14a15 a21a22a23
a11 a12 a21 a22=6
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