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n^2+1/n2^n的和
n/n2+1+n/n2+22
n/n2+n/n2+1*2+n/n2+2*3
n(n2-1)
n=n2/n1
n/(n2+1)+n/(n2+4)
n2+(n+1)2+(n+2)2+…(2n-1)2
n/2^n-1的和
∑[n(n+1)/2^n]的和
n2^n-1
n2(arctanπ/n-arctanπ/n+1)
n2^n-1求和
n与n2
n2-n+11
n^2/n!的和
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